4/z+3/2z=1/3

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Solution for 4/z+3/2z=1/3 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

(3/2)*z+4/z = 1/3 // - 1/3

(3/2)*z+4/z-(1/3) = 0

(3/2)*z+4/z-1/3 = 0

3/2*z^1+4*z^-1-1/3*z^0 = 0

(3/2*z^2-1/3*z^1+4*z^0)/(z^1) = 0 // * z^2

z^1*(3/2*z^2-1/3*z^1+4*z^0) = 0

z^1

(3/2)*z^2+(-1/3)*z+4 = 0

(3/2)*z^2+(-1/3)*z+4 = 0

DELTA = (-1/3)^2-(4*4*(3/2))

DELTA = -215/9

DELTA < 0

z in { } 

z belongs to the empty set

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