40(2x+2)=35(3x-7)

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Solution for 40(2x+2)=35(3x-7) equation: 



40(2x+2)=35(3x-7)

We move all terms to the left:

40(2x+2)-(35(3x-7))=0

We multiply parentheses

80x-(35(3x-7))+80=0



We calculate terms in parentheses: -(35(3x-7)), so:

35(3x-7)

We multiply parentheses

105x-245

Back to the equation:

-(105x-245)



We get rid of parentheses

80x-105x+245+80=0

We add all the numbers together, and all the variables

-25x+325=0

We move all terms containing x to the left, all other terms to the right

-25x=-325

x=-325/-25

x=+13

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