40(2x-)=8(x+4)+3x

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Solution for 40(2x-)=8(x+4)+3x equation:



40(2x-)=8(x+4)+3x
We move all terms to the left:
40(2x-)-(8(x+4)+3x)=0
We add all the numbers together, and all the variables
40(+2x)-(8(x+4)+3x)=0
We multiply parentheses
80x-(8(x+4)+3x)=0
We calculate terms in parentheses: -(8(x+4)+3x), so:
8(x+4)+3x
We add all the numbers together, and all the variables
3x+8(x+4)
We multiply parentheses
3x+8x+32
We add all the numbers together, and all the variables
11x+32
Back to the equation:
-(11x+32)
We get rid of parentheses
80x-11x-32=0
We add all the numbers together, and all the variables
69x-32=0
We move all terms containing x to the left, all other terms to the right
69x=32
x=32/69
x=32/69

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