40(2x-1)=8(x+4)3x

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Solution for 40(2x-1)=8(x+4)3x equation: 



40(2x-1)=8(x+4)3x

We move all terms to the left:

40(2x-1)-(8(x+4)3x)=0

We multiply parentheses

80x-(8(x+4)3x)-40=0



We calculate terms in parentheses: -(8(x+4)3x), so:

8(x+4)3x

We multiply parentheses

24x^2+96x

Back to the equation:

-(24x^2+96x)



We get rid of parentheses

-24x^2+80x-96x-40=0

We add all the numbers together, and all the variables

-24x^2-16x-40=0

a = -24; b = -16; c = -40;
Δ = b2-4ac
Δ = -162-4·(-24)·(-40)
Δ = -3584
Delta is less than zero, so there is no solution for the equation

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