40(3x-1)+3(x+4)=2(3)+6(2x+4)

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Solution for 40(3x-1)+3(x+4)=2(3)+6(2x+4) equation:


40(3x-1)+3(x+4)=2(3)+6(2x+4)

We simplify the equation to the form, which is simple to understand 
40(3x-1)+3(x+4)=2(3)+6(2x+4)

Reorder the terms in parentheses
+(+120x-40)+3*(x+4)=2*(3)+6*(2x+4)

Remove unnecessary parentheses
+120x-40+3+*(+x+4+)=+2+*(+3+)+6+*(+2x+4+)

Reorder the terms in parentheses
+120x-40+(+3x+12)=2*(3)+6*(2x+4)

Remove unnecessary parentheses
+120x-40+3x+12=+2+*(+3+)+6+*(+2x+4+)

Reorder the terms in parentheses
+120x-40+3x+12=+(+6)+6*(2x+4)

Remove unnecessary parentheses
+120x-40+3x+12=+6+6+*(+2x+4+)

Reorder the terms in parentheses
+120x-40+3x+12=+6+(+12x+24)

Remove unnecessary parentheses
+120x-40+3x+12=+6+12x+24

We move all terms containing x to the left and all other terms to the right. 
+120x+3x-12x=+6+24+40-12

We simplify left and right side of the equation. 
+111x=+58

We divide both sides of the equation by 111 to get x. 
x=0.52252252252252

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