40(a-1)-45(2a-+1)=12(a-2)

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Solution for 40(a-1)-45(2a-+1)=12(a-2) equation: 



40(a-1)-45(2a-+1)=12(a-2)

We move all terms to the left:

40(a-1)-45(2a-+1)-(12(a-2))=0

We add all the numbers together, and all the variables

40(a-1)-45(+2a)-(12(a-2))=0

We multiply parentheses

40a-90a-(12(a-2))-40=0



We calculate terms in parentheses: -(12(a-2)), so:

12(a-2)

We multiply parentheses

12a-24

Back to the equation:

-(12a-24)



We add all the numbers together, and all the variables

-50a-(12a-24)-40=0

We get rid of parentheses

-50a-12a+24-40=0

We add all the numbers together, and all the variables

-62a-16=0

We move all terms containing a to the left, all other terms to the right

-62a=16

a=16/-62

a=-8/31

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