40(a-3)=24a-28

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Solution for 40(a-3)=24a-28 equation: 



40(a-3)=24a-28

We move all terms to the left:

40(a-3)-(24a-28)=0

We multiply parentheses

40a-(24a-28)-120=0

We get rid of parentheses

40a-24a+28-120=0

We add all the numbers together, and all the variables

16a-92=0

We move all terms containing a to the left, all other terms to the right

16a=92

a=92/16

a=5+3/4

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