40(x+3)-20=18

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Solution for 40(x+3)-20=18 equation: 



40(x+3)-20=18

We move all terms to the left:

40(x+3)-20-(18)=0

We add all the numbers together, and all the variables

40(x+3)-38=0

We multiply parentheses

40x+120-38=0

We add all the numbers together, and all the variables

40x+82=0

We move all terms containing x to the left, all other terms to the right

40x=-82

x=-82/40

x=-2+1/20

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