40(x-1)=-8(5-x)+32x

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Solution for 40(x-1)=-8(5-x)+32x equation:


Simplifying
40(x + -1) = -8(5 + -1x) + 32x

Reorder the terms:
40(-1 + x) = -8(5 + -1x) + 32x
(-1 * 40 + x * 40) = -8(5 + -1x) + 32x
(-40 + 40x) = -8(5 + -1x) + 32x
-40 + 40x = (5 * -8 + -1x * -8) + 32x
-40 + 40x = (-40 + 8x) + 32x

Combine like terms: 8x + 32x = 40x
-40 + 40x = -40 + 40x

Add '40' to each side of the equation.
-40 + 40 + 40x = -40 + 40 + 40x

Combine like terms: -40 + 40 = 0
0 + 40x = -40 + 40 + 40x
40x = -40 + 40 + 40x

Combine like terms: -40 + 40 = 0
40x = 0 + 40x
40x = 40x

Add '-40x' to each side of the equation.
40x + -40x = 40x + -40x

Combine like terms: 40x + -40x = 0
0 = 40x + -40x

Combine like terms: 40x + -40x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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