40(x-3)+15=30(x+4)+24x

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Solution for 40(x-3)+15=30(x+4)+24x equation: 



40(x-3)+15=30(x+4)+24x

We move all terms to the left:

40(x-3)+15-(30(x+4)+24x)=0

We multiply parentheses

40x-(30(x+4)+24x)-120+15=0



We calculate terms in parentheses: -(30(x+4)+24x), so:

30(x+4)+24x

We add all the numbers together, and all the variables

24x+30(x+4)

We multiply parentheses

24x+30x+120

We add all the numbers together, and all the variables

54x+120

Back to the equation:

-(54x+120)



We add all the numbers together, and all the variables

40x-(54x+120)-105=0

We get rid of parentheses

40x-54x-120-105=0

We add all the numbers together, and all the variables

-14x-225=0

We move all terms containing x to the left, all other terms to the right

-14x=225

x=225/-14

x=-16+1/14

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