40(y+2)=5(7y+8)

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Solution for 40(y+2)=5(7y+8) equation:


Simplifying
40(y + 2) = 5(7y + 8)

Reorder the terms:
40(2 + y) = 5(7y + 8)
(2 * 40 + y * 40) = 5(7y + 8)
(80 + 40y) = 5(7y + 8)

Reorder the terms:
80 + 40y = 5(8 + 7y)
80 + 40y = (8 * 5 + 7y * 5)
80 + 40y = (40 + 35y)

Solving
80 + 40y = 40 + 35y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-35y' to each side of the equation.
80 + 40y + -35y = 40 + 35y + -35y

Combine like terms: 40y + -35y = 5y
80 + 5y = 40 + 35y + -35y

Combine like terms: 35y + -35y = 0
80 + 5y = 40 + 0
80 + 5y = 40

Add '-80' to each side of the equation.
80 + -80 + 5y = 40 + -80

Combine like terms: 80 + -80 = 0
0 + 5y = 40 + -80
5y = 40 + -80

Combine like terms: 40 + -80 = -40
5y = -40

Divide each side by '5'.
y = -8

Simplifying
y = -8

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