40(y+2)=6y+2

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Solution for 40(y+2)=6y+2 equation: 



40(y+2)=6y+2

We move all terms to the left:

40(y+2)-(6y+2)=0

We multiply parentheses

40y-(6y+2)+80=0

We get rid of parentheses

40y-6y-2+80=0

We add all the numbers together, and all the variables

34y+78=0

We move all terms containing y to the left, all other terms to the right

34y=-78

y=-78/34

y=-2+5/17

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