40+(3c+4)=2(c+3)+3

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Solution for 40+(3c+4)=2(c+3)+3 equation: 



40+(3c+4)=2(c+3)+3

We move all terms to the left:

40+(3c+4)-(2(c+3)+3)=0

We get rid of parentheses

3c-(2(c+3)+3)+4+40=0



We calculate terms in parentheses: -(2(c+3)+3), so:

2(c+3)+3

We multiply parentheses

2c+6+3

We add all the numbers together, and all the variables

2c+9

Back to the equation:

-(2c+9)



We add all the numbers together, and all the variables

3c-(2c+9)+44=0

We get rid of parentheses

3c-2c-9+44=0

We add all the numbers together, and all the variables

c+35=0

We move all terms containing c to the left, all other terms to the right

c=-35

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