40+(5/6)=3y-(7/12)

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Solution for 40+(5/6)=3y-(7/12) equation: 



40+(5/6)=3y-(7/12)

We move all terms to the left:

40+(5/6)-(3y-(7/12))=0

We add all the numbers together, and all the variables

-(3y-(+7/12))+40+(+5/6)=0

We get rid of parentheses

-(3y-(+7/12))+40+5/6=0

We calculate fractions


(-(3y-(+7*6)/()+()/()+40=0

We can not solve this equation

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