40+(60x-55)=30-(45x-20)+10

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Solution for 40+(60x-55)=30-(45x-20)+10 equation: 



40+(60x-55)=30-(45x-20)+10

We move all terms to the left:

40+(60x-55)-(30-(45x-20)+10)=0

We get rid of parentheses

60x-(30-(45x-20)+10)-55+40=0



We calculate terms in parentheses: -(30-(45x-20)+10), so:

30-(45x-20)+10

determiningTheFunctionDomain
-(45x-20)+30+10

We add all the numbers together, and all the variables

-(45x-20)+40

We get rid of parentheses

-45x+20+40

We add all the numbers together, and all the variables

-45x+60

Back to the equation:

-(-45x+60)



We add all the numbers together, and all the variables

60x-(-45x+60)-15=0

We get rid of parentheses

60x+45x-60-15=0

We add all the numbers together, and all the variables

105x-75=0

We move all terms containing x to the left, all other terms to the right

105x=75

x=75/105

x=5/7

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