40+1/3+(x-20)+(x-10)=360

Solution for 40+1/3+(x-20)+(x-10)=360 equation:

40+1/3+(x-20)+(x-10)=360

We move all terms to the left:

40+1/3+(x-20)+(x-10)-(360)=0

determiningTheFunctionDomain
(x-20)+(x-10)+40-360+1/3=0

We add all the numbers together, and all the variables

(x-20)+(x-10)-320+1/3=0

We get rid of parentheses

x+x-20-10-320+1/3=0

We multiply all the terms by the denominator


x*3+x*3+1-20*3-10*3-320*3=0

We add all the numbers together, and all the variables

x*3+x*3-1049=0

Wy multiply elements

3x+3x-1049=0

We add all the numbers together, and all the variables

6x-1049=0

We move all terms containing x to the left, all other terms to the right

6x=1049

x=1049/6

x=174+5/6