40+1j=2(4j-13)

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Solution for 40+1j=2(4j-13) equation: 



40+1j=2(4j-13)

We move all terms to the left:

40+1j-(2(4j-13))=0

We add all the numbers together, and all the variables

j-(2(4j-13))+40=0



We calculate terms in parentheses: -(2(4j-13)), so:

2(4j-13)

We multiply parentheses

8j-26

Back to the equation:

-(8j-26)



We get rid of parentheses

j-8j+26+40=0

We add all the numbers together, and all the variables

-7j+66=0

We move all terms containing j to the left, all other terms to the right

-7j=-66

j=-66/-7

j=9+3/7

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