40+2n=2(6+3n)

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Solution for 40+2n=2(6+3n) equation: 



40+2n=2(6+3n)

We move all terms to the left:

40+2n-(2(6+3n))=0

We add all the numbers together, and all the variables

2n-(2(3n+6))+40=0



We calculate terms in parentheses: -(2(3n+6)), so:

2(3n+6)

We multiply parentheses

6n+12

Back to the equation:

-(6n+12)



We get rid of parentheses

2n-6n-12+40=0

We add all the numbers together, and all the variables

-4n+28=0

We move all terms containing n to the left, all other terms to the right

-4n=-28

n=-28/-4

n=+7

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