40+3x=10x+19

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Solution for 40+3x=10x+19 equation: 



40+3x=10x+19

We move all terms to the left:

40+3x-(10x+19)=0

We get rid of parentheses

3x-10x-19+40=0

We add all the numbers together, and all the variables

-7x+21=0

We move all terms containing x to the left, all other terms to the right

-7x=-21

x=-21/-7

x=+3

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