40+3x=3x+5(1-x)

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Solution for 40+3x=3x+5(1-x) equation: 



40+3x=3x+5(1-x)

We move all terms to the left:

40+3x-(3x+5(1-x))=0

We add all the numbers together, and all the variables

3x-(3x+5(-1x+1))+40=0



We calculate terms in parentheses: -(3x+5(-1x+1)), so:

3x+5(-1x+1)

We multiply parentheses

3x-5x+5

We add all the numbers together, and all the variables

-2x+5

Back to the equation:

-(-2x+5)



We get rid of parentheses

3x+2x-5+40=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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