40+3x=4(-x+5)-36

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Solution for 40+3x=4(-x+5)-36 equation: 



40+3x=4(-x+5)-36

We move all terms to the left:

40+3x-(4(-x+5)-36)=0

We add all the numbers together, and all the variables

3x-(4(-1x+5)-36)+40=0



We calculate terms in parentheses: -(4(-1x+5)-36), so:

4(-1x+5)-36

We multiply parentheses

-4x+20-36

We add all the numbers together, and all the variables

-4x-16

Back to the equation:

-(-4x-16)



We get rid of parentheses

3x+4x+16+40=0

We add all the numbers together, and all the variables

7x+56=0

We move all terms containing x to the left, all other terms to the right

7x=-56

x=-56/7

x=-8

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