40+3x=4(-x+6)-33

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Solution for 40+3x=4(-x+6)-33 equation: 



40+3x=4(-x+6)-33

We move all terms to the left:

40+3x-(4(-x+6)-33)=0

We add all the numbers together, and all the variables

3x-(4(-1x+6)-33)+40=0



We calculate terms in parentheses: -(4(-1x+6)-33), so:

4(-1x+6)-33

We multiply parentheses

-4x+24-33

We add all the numbers together, and all the variables

-4x-9

Back to the equation:

-(-4x-9)



We get rid of parentheses

3x+4x+9+40=0

We add all the numbers together, and all the variables

7x+49=0

We move all terms containing x to the left, all other terms to the right

7x=-49

x=-49/7

x=-7

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