40+3x=73-2x

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Solution for 40+3x=73-2x equation: 



40+3x=73-2x

We move all terms to the left:

40+3x-(73-2x)=0

We add all the numbers together, and all the variables

3x-(-2x+73)+40=0

We get rid of parentheses

3x+2x-73+40=0

We add all the numbers together, and all the variables

5x-33=0

We move all terms containing x to the left, all other terms to the right

5x=33

x=33/5

x=6+3/5

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