40+3x=8(1+2x)+3x

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Solution for 40+3x=8(1+2x)+3x equation: 



40+3x=8(1+2x)+3x

We move all terms to the left:

40+3x-(8(1+2x)+3x)=0

We add all the numbers together, and all the variables

3x-(8(2x+1)+3x)+40=0



We calculate terms in parentheses: -(8(2x+1)+3x), so:

8(2x+1)+3x

We add all the numbers together, and all the variables

3x+8(2x+1)

We multiply parentheses

3x+16x+8

We add all the numbers together, and all the variables

19x+8

Back to the equation:

-(19x+8)



We get rid of parentheses

3x-19x-8+40=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2

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