40+4x=5(-x+2)-42

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Solution for 40+4x=5(-x+2)-42 equation: 



40+4x=5(-x+2)-42

We move all terms to the left:

40+4x-(5(-x+2)-42)=0

We add all the numbers together, and all the variables

4x-(5(-1x+2)-42)+40=0



We calculate terms in parentheses: -(5(-1x+2)-42), so:

5(-1x+2)-42

We multiply parentheses

-5x+10-42

We add all the numbers together, and all the variables

-5x-32

Back to the equation:

-(-5x-32)



We get rid of parentheses

4x+5x+32+40=0

We add all the numbers together, and all the variables

9x+72=0

We move all terms containing x to the left, all other terms to the right

9x=-72

x=-72/9

x=-8

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