40+5y-4=16y-1-4y

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Solution for 40+5y-4=16y-1-4y equation: 



40+5y-4=16y-1-4y

We move all terms to the left:

40+5y-4-(16y-1-4y)=0

We add all the numbers together, and all the variables

5y-(12y-1)+40-4=0

We add all the numbers together, and all the variables

5y-(12y-1)+36=0

We get rid of parentheses

5y-12y+1+36=0

We add all the numbers together, and all the variables

-7y+37=0

We move all terms containing y to the left, all other terms to the right

-7y=-37

y=-37/-7

y=5+2/7

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