40+6x=3(-x+3)-32

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Solution for 40+6x=3(-x+3)-32 equation: 



40+6x=3(-x+3)-32

We move all terms to the left:

40+6x-(3(-x+3)-32)=0

We add all the numbers together, and all the variables

6x-(3(-1x+3)-32)+40=0



We calculate terms in parentheses: -(3(-1x+3)-32), so:

3(-1x+3)-32

We multiply parentheses

-3x+9-32

We add all the numbers together, and all the variables

-3x-23

Back to the equation:

-(-3x-23)



We get rid of parentheses

6x+3x+23+40=0

We add all the numbers together, and all the variables

9x+63=0

We move all terms containing x to the left, all other terms to the right

9x=-63

x=-63/9

x=-7

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