40+7y=2(4y+4)+2(2y+6)

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Solution for 40+7y=2(4y+4)+2(2y+6) equation: 



40+7y=2(4y+4)+2(2y+6)

We move all terms to the left:

40+7y-(2(4y+4)+2(2y+6))=0



We calculate terms in parentheses: -(2(4y+4)+2(2y+6)), so:

2(4y+4)+2(2y+6)

We multiply parentheses

8y+4y+8+12

We add all the numbers together, and all the variables

12y+20

Back to the equation:

-(12y+20)



We get rid of parentheses

7y-12y-20+40=0

We add all the numbers together, and all the variables

-5y+20=0

We move all terms containing y to the left, all other terms to the right

-5y=-20

y=-20/-5

y=+4

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