40+n=2(n+14)

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Solution for 40+n=2(n+14) equation: 



40+n=2(n+14)

We move all terms to the left:

40+n-(2(n+14))=0



We calculate terms in parentheses: -(2(n+14)), so:

2(n+14)

We multiply parentheses

2n+28

Back to the equation:

-(2n+28)



We get rid of parentheses

n-2n-28+40=0

We add all the numbers together, and all the variables

-1n+12=0

We move all terms containing n to the left, all other terms to the right

-n=-12

n=-12/-1

n=+12

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