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40.500=30x-0.002x^2
We move all terms to the left:
40.500-(30x-0.002x^2)=0
We add all the numbers together, and all the variables
-(30x-0.002x^2)+40.5=0
We get rid of parentheses
0.002x^2-30x+40.5=0
a = 0.002; b = -30; c = +40.5;
Δ = b2-4ac
Δ = -302-4·0.002·40.5
Δ = 899.676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-\sqrt{899.676}}{2*0.002}=\frac{30-\sqrt{899.676}}{0.004} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+\sqrt{899.676}}{2*0.002}=\frac{30+\sqrt{899.676}}{0.004} $
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