40-(30+4)=4(c+5)+0

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Solution for 40-(30+4)=4(c+5)+0 equation: 



40-(30+4)=4(c+5)+0

We move all terms to the left:

40-(30+4)-(4(c+5)+0)=0

We add all the numbers together, and all the variables

-(4(c+5)+0)+40-34=0

We add all the numbers together, and all the variables

-(4(c+5)+0)+6=0



We calculate terms in parentheses: -(4(c+5)+0), so:

4(c+5)+0

We add all the numbers together, and all the variables

4(c+5)

We multiply parentheses

4c+20

Back to the equation:

-(4c+20)



We get rid of parentheses

-4c-20+6=0

We add all the numbers together, and all the variables

-4c-14=0

We move all terms containing c to the left, all other terms to the right

-4c=14

c=14/-4

c=-3+1/2

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