40-(3c+4)-(c+5)+c)=0

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Solution for 40-(3c+4)-(c+5)+c)=0 equation: 



40-(3c+4)-(c+5)+c)=0

We get rid of parentheses

-3c-c+c)+40-4-5=0

We add all the numbers together, and all the variables

-4c+c)+40-4-5=0

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