40-(3c+4)=2(c+3)+c

Solution for 40-(3c+4)=2(c+3)+c equation:

Simplifying
40 + -1(3c + 4) = 2(c + 3) + c

Reorder the terms:
40 + -1(4 + 3c) = 2(c + 3) + c
40 + (4 * -1 + 3c * -1) = 2(c + 3) + c
40 + (-4 + -3c) = 2(c + 3) + c

Combine like terms: 40 + -4 = 36
36 + -3c = 2(c + 3) + c

Reorder the terms:
36 + -3c = 2(3 + c) + c
36 + -3c = (3 * 2 + c * 2) + c
36 + -3c = (6 + 2c) + c

Combine like terms: 2c + c = 3c
36 + -3c = 6 + 3c

Solving
36 + -3c = 6 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
36 + -3c + -3c = 6 + 3c + -3c

Combine like terms: -3c + -3c = -6c
36 + -6c = 6 + 3c + -3c

Combine like terms: 3c + -3c = 0
36 + -6c = 6 + 0
36 + -6c = 6

Add '-36' to each side of the equation.
36 + -36 + -6c = 6 + -36

Combine like terms: 36 + -36 = 0
0 + -6c = 6 + -36
-6c = 6 + -36

Combine like terms: 6 + -36 = -30
-6c = -30

Divide each side by '-6'.
c = 5

Simplifying
c = 5