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40-(3c+4)=2(c+6)-c
We move all terms to the left:
40-(3c+4)-(2(c+6)-c)=0
We get rid of parentheses
-3c-(2(c+6)-c)-4+40=0
We calculate terms in parentheses: -(2(c+6)-c), so:We add all the numbers together, and all the variables
2(c+6)-c
We add all the numbers together, and all the variables
-1c+2(c+6)
We multiply parentheses
-1c+2c+12
We add all the numbers together, and all the variables
c+12
Back to the equation:
-(c+12)
-3c-(c+12)+36=0
We get rid of parentheses
-3c-c-12+36=0
We add all the numbers together, and all the variables
-4c+24=0
We move all terms containing c to the left, all other terms to the right
-4c=-24
c=-24/-4
c=+6
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