40-(3c+4)=4(c+5+c

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Solution for 40-(3c+4)=4(c+5+c equation: 



40-(3c+4)=4(c+5+c

We move all terms to the left:

40-(3c+4)-(4(c+5+c)=0

We add all the numbers together, and all the variables

-(3c+4)-(4(2c+5)+40=0

We get rid of parentheses

-3c-(4(2c+5)+40-4=0

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