40-12=4(x-5)

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Solution for 40-12=4(x-5) equation:



40-12=4(x-5)
We move all terms to the left:
40-12-(4(x-5))=0
We add all the numbers together, and all the variables
-(4(x-5))+28=0
We calculate terms in parentheses: -(4(x-5)), so:
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
We get rid of parentheses
-4x+20+28=0
We add all the numbers together, and all the variables
-4x+48=0
We move all terms containing x to the left, all other terms to the right
-4x=-48
x=-48/-4
x=+12

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