40-2(2c+3)=2(c+6)+c

Solution for 40-2(2c+3)=2(c+6)+c equation:

40-2(2c+3)=2(c+6)+c

We move all terms to the left:

40-2(2c+3)-(2(c+6)+c)=0

We multiply parentheses

-4c-(2(c+6)+c)-6+40=0


We calculate terms in parentheses: -(2(c+6)+c), so:

2(c+6)+c

We add all the numbers together, and all the variables

c+2(c+6)

We multiply parentheses

c+2c+12

We add all the numbers together, and all the variables

3c+12

Back to the equation:

-(3c+12)


We add all the numbers together, and all the variables

-4c-(3c+12)+34=0

We get rid of parentheses

-4c-3c-12+34=0

We add all the numbers together, and all the variables

-7c+22=0

We move all terms containing c to the left, all other terms to the right

-7c=-22

c=-22/-7

c=3+1/7