40-2x=5(1+8x)-7x

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Solution for 40-2x=5(1+8x)-7x equation: 



40-2x=5(1+8x)-7x

We move all terms to the left:

40-2x-(5(1+8x)-7x)=0

We add all the numbers together, and all the variables

-2x-(5(8x+1)-7x)+40=0



We calculate terms in parentheses: -(5(8x+1)-7x), so:

5(8x+1)-7x

We add all the numbers together, and all the variables

-7x+5(8x+1)

We multiply parentheses

-7x+40x+5

We add all the numbers together, and all the variables

33x+5

Back to the equation:

-(33x+5)



We get rid of parentheses

-2x-33x-5+40=0

We add all the numbers together, and all the variables

-35x+35=0

We move all terms containing x to the left, all other terms to the right

-35x=-35

x=-35/-35

x=1

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