40-2x=6-7(3x+6)

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Solution for 40-2x=6-7(3x+6) equation: 



40-2x=6-7(3x+6)

We move all terms to the left:

40-2x-(6-7(3x+6))=0



We calculate terms in parentheses: -(6-7(3x+6)), so:

6-7(3x+6)

determiningTheFunctionDomain
-7(3x+6)+6

We multiply parentheses

-21x-42+6

We add all the numbers together, and all the variables

-21x-36

Back to the equation:

-(-21x-36)



We get rid of parentheses

-2x+21x+36+40=0

We add all the numbers together, and all the variables

19x+76=0

We move all terms containing x to the left, all other terms to the right

19x=-76

x=-76/19

x=-4

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