40-2y=30-(3y/4)

Solution for 40-2y=30-(3y/4) equation:

40-2y=30-(3y/4)

We move all terms to the left:

40-2y-(30-(3y/4))=0

We add all the numbers together, and all the variables

-2y-(30-(+3y/4))+40=0

We multiply all the terms by the denominator


-2y*4))-(30-(+3y+40*4))=0

We add all the numbers together, and all the variables

-2y*4))-(30-(3y+160))=0

We add all the numbers together, and all the variables

-2y*4))-(30-(3y=0

Wy multiply elements

-8y^2=0

a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-16}=0$