40-4(n-26)=-16+15(n-21)

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Solution for 40-4(n-26)=-16+15(n-21) equation: 



40-4(n-26)=-16+15(n-21)

We move all terms to the left:

40-4(n-26)-(-16+15(n-21))=0

We multiply parentheses

-4n-(-16+15(n-21))+104+40=0



We calculate terms in parentheses: -(-16+15(n-21)), so:

-16+15(n-21)

determiningTheFunctionDomain
15(n-21)-16

We multiply parentheses

15n-315-16

We add all the numbers together, and all the variables

15n-331

Back to the equation:

-(15n-331)



We add all the numbers together, and all the variables

-4n-(15n-331)+144=0

We get rid of parentheses

-4n-15n+331+144=0

We add all the numbers together, and all the variables

-19n+475=0

We move all terms containing n to the left, all other terms to the right

-19n=-475

n=-475/-19

n=+25

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