40-4b=-8(4+2b)

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Solution for 40-4b=-8(4+2b) equation: 



40-4b=-8(4+2b)

We move all terms to the left:

40-4b-(-8(4+2b))=0

We add all the numbers together, and all the variables

-4b-(-8(2b+4))+40=0



We calculate terms in parentheses: -(-8(2b+4)), so:

-8(2b+4)

We multiply parentheses

-16b-32

Back to the equation:

-(-16b-32)



We get rid of parentheses

-4b+16b+32+40=0

We add all the numbers together, and all the variables

12b+72=0

We move all terms containing b to the left, all other terms to the right

12b=-72

b=-72/12

b=-6

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