40-5(2-3x)=5(6-x)

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Solution for 40-5(2-3x)=5(6-x) equation: 



40-5(2-3x)=5(6-x)

We move all terms to the left:

40-5(2-3x)-(5(6-x))=0

We add all the numbers together, and all the variables

-5(-3x+2)-(5(-1x+6))+40=0

We multiply parentheses

15x-(5(-1x+6))-10+40=0



We calculate terms in parentheses: -(5(-1x+6)), so:

5(-1x+6)

We multiply parentheses

-5x+30

Back to the equation:

-(-5x+30)



We add all the numbers together, and all the variables

15x-(-5x+30)+30=0

We get rid of parentheses

15x+5x-30+30=0

We add all the numbers together, and all the variables

20x=0

x=0/20

x=0

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