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40-6a=2-8(a-3)
We move all terms to the left:
40-6a-(2-8(a-3))=0
We calculate terms in parentheses: -(2-8(a-3)), so:We get rid of parentheses
2-8(a-3)
determiningTheFunctionDomain -8(a-3)+2
We multiply parentheses
-8a+24+2
We add all the numbers together, and all the variables
-8a+26
Back to the equation:
-(-8a+26)
-6a+8a-26+40=0
We add all the numbers together, and all the variables
2a+14=0
We move all terms containing a to the left, all other terms to the right
2a=-14
a=-14/2
a=-7
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