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40-6x+12=3*3-(x+5)
We move all terms to the left:
40-6x+12-(3*3-(x+5))=0
We add all the numbers together, and all the variables
-6x-(3*3-(x+5))+52=0
We calculate terms in parentheses: -(3*3-(x+5)), so:We get rid of parentheses
3*3-(x+5)
determiningTheFunctionDomain -(x+5)+3*3
We add all the numbers together, and all the variables
-(x+5)+9
We get rid of parentheses
-x-5+9
We add all the numbers together, and all the variables
-1x+4
Back to the equation:
-(-1x+4)
-6x+1x-4+52=0
We add all the numbers together, and all the variables
-5x+48=0
We move all terms containing x to the left, all other terms to the right
-5x=-48
x=-48/-5
x=9+3/5
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