40-9x=-5(6x+3)-5(-8-4x)

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Solution for 40-9x=-5(6x+3)-5(-8-4x) equation: 



40-9x=-5(6x+3)-5(-8-4x)

We move all terms to the left:

40-9x-(-5(6x+3)-5(-8-4x))=0

We add all the numbers together, and all the variables

-9x-(-5(6x+3)-5(-4x-8))+40=0



We calculate terms in parentheses: -(-5(6x+3)-5(-4x-8)), so:

-5(6x+3)-5(-4x-8)

We multiply parentheses

-30x+20x-15+40

We add all the numbers together, and all the variables

-10x+25

Back to the equation:

-(-10x+25)



We get rid of parentheses

-9x+10x-25+40=0

We add all the numbers together, and all the variables

x+15=0

We move all terms containing x to the left, all other terms to the right

x=-15

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