40-n=-4(n-5)-1

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Solution for 40-n=-4(n-5)-1 equation:



40-n=-4(n-5)-1
We move all terms to the left:
40-n-(-4(n-5)-1)=0
We add all the numbers together, and all the variables
-1n-(-4(n-5)-1)+40=0
We calculate terms in parentheses: -(-4(n-5)-1), so:
-4(n-5)-1
We multiply parentheses
-4n+20-1
We add all the numbers together, and all the variables
-4n+19
Back to the equation:
-(-4n+19)
We get rid of parentheses
-1n+4n-19+40=0
We add all the numbers together, and all the variables
3n+21=0
We move all terms containing n to the left, all other terms to the right
3n=-21
n=-21/3
n=-7

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