40/x-40x+39=0

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Solution for 40/x-40x+39=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

40/x-(40*x)+39 = 0

40/x-40*x+39 = 0

40*x^-1-40*x^1+39*x^0 = 0

(39*x^1-40*x^2+40*x^0)/(x^1) = 0 // * x^2

x^1*(39*x^1-40*x^2+40*x^0) = 0

x^1

39*x-40*x^2+40 = 0

39*x-40*x^2+40 = 0

DELTA = 39^2-(-40*4*40)

DELTA = 7921

DELTA > 0

x = (7921^(1/2)-39)/(-40*2) or x = (-7921^(1/2)-39)/(-40*2)

x = -5/8 or x = 8/5

x in { -5/8, 8/5} 

x in { -5/8, 8/5 }

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