40/y*12y=8

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Solution for 40/y*12y=8 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

12*(40/y)*y = 8 // - 8

12*(40/y)*y-8 = 0

472 = 0

y belongs to the empty set

y belongs to the empty set

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