400=2x+2(2/3x)

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Solution for 400=2x+2(2/3x) equation: 



400=2x+2(2/3x)

We move all terms to the left:

400-(2x+2(2/3x))=0



Domain of the equation: 3x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(2x+2(+2/3x))+400=0

We multiply all the terms by the denominator


-(2x+2(+2+400*3x))=0



We calculate terms in parentheses: -(2x+2(+2+400*3x)), so:

2x+2(+2+400*3x)

We add all the numbers together, and all the variables

2x+2(400*3x+2)

We multiply parentheses

2x+2400x+4

We add all the numbers together, and all the variables

2402x+4

Back to the equation:

-(2402x+4)



We get rid of parentheses

-2402x-4=0

We move all terms containing x to the left, all other terms to the right

-2402x=4

x=4/-2402

x=-2/1201

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